Tutorial · example 1 of 4

R-001 — minimum shaft shoulder

Follow the actual features and contributor order in tutorial.stack. Learn where to click, why each row is there, and how Stack checks a 4.5 mm minimum shoulder using a nominal of 5 mm and the tolerances shown on the drawing.

This is a guided, schematic replay, not a live copy of Stack. Open the example in the application to carry out the actions. R-002, R-003 and R-004 will be separate lessons; only R-001 is available here so far.

Stack · R-001 · ProjectStep 1 / 18
ProjectPartsFeaturesRequirementsCalculationsResults
Ø20 ±0.10Ø10 ±0.05Ø0.25 ⓂA ⓂAR-001 ≥ 4.51: −55: +102: Position3: MMC ← Ø204: MMB ← Ø10
Project
tutorial-test
Units / standard
Metric / ASME Y14.5-2018
Temperatures
−50 / 20 / 250 °C

Open the tutorial project

Project → Open… → examples/tutorial.stack

Start with the supplied project and choose R-001, Min flat. The saved project name is tutorial-test. Work on a copy and enter the values shown in this lesson: MIN 4.5, datum diameter ±0.05, larger diameter ±0.10 and position Ø0.25. These are the updated inputs for this walkthrough. All dimensions in this lesson are millimetres.

Metric · ASME Y14.5-2018 · room temperature 20 °C

12 seconds per step · pause to work in the app

Check the result yourself

At 20 °C, add all five declared half-ranges: 0.025 + 0.125 + 0.100 + 0.050 + 0.050 = 0.350 mm. The grid total and WC use the same sum:

MIN = 5 − 0.350 = 4.650 mm
MAX = 5 + 0.350 = 5.350 mm

Compare MIN with the requirement, not the nominal: 4.650 ≥ 4.500, a margin of 0.150 mm. The room-temperature requirement passes. This verdict applies to the inputs declared in this sheet. Analyse another limiting material state in a separate sheet when needed.

For the controls, use the Manual. For the derivation of the methods, use the White paper. For instructor-led help, see Training & Consulting.