Tutorial · example 1 of 4
R-001 — minimum shaft shoulder
Follow the actual features and contributor order in tutorial.stack. Learn where to click, why each row is there, and how Stack checks a 4.5 mm minimum shoulder using a nominal of 5 mm and the tolerances shown on the drawing.
This is a guided, schematic replay, not a live copy of Stack. Open the example in the application to carry out the actions. R-002, R-003 and R-004 will be separate lessons; only R-001 is available here so far.
- Project
- tutorial-test
- Units / standard
- Metric / ASME Y14.5-2018
- Temperatures
- −50 / 20 / 250 °C
Open the tutorial project
Project → Open… → examples/tutorial.stack
Start with the supplied project and choose R-001, Min flat. The saved project name is tutorial-test. Work on a copy and enter the values shown in this lesson: MIN 4.5, datum diameter ±0.05, larger diameter ±0.10 and position Ø0.25. These are the updated inputs for this walkthrough. All dimensions in this lesson are millimetres.
Metric · ASME Y14.5-2018 · room temperature 20 °C
Check the result yourself
At 20 °C, the ordinary half-ranges are 0.025 + 0.125 + 0.050 = 0.200 mm. Because the linked bonuses have different availability at the two extremes:
MAX = 5 + 0.200 + 0.050 = 5.250 mm
Compare MIN with the requirement, not the nominal: 4.700 ≥ 4.500, a margin of 0.200 mm. The room-temperature requirement passes. Simply summing every maximum bonus on both sides would give the wrong band.
For the controls, use the Manual. For the derivation of the methods, use the White paper. For instructor-led help, see Training & Consulting.